Question

qual é o resultado da equação x²+8x-4=0

Answer 1

$x^{2} +8x-4=0$

Δ = $8^{2} -4(-4)$
Δ = $8^{2} +16$
Δ = $64 + 16$
Δ = $80$

$x_{1,2}=$ -8 ± √80 / 2

$x_{1,2}$ = (-8)± 8,944 / 2

$x_{1} = \frac{(-8)+8,944}{2}$

$x_{1} = \frac{0,944}{2}$

$x_{1} = \frac{1}{2,118}$

$x_{2} = \frac{-8-8,944}{2}$

$x_{2} = \frac{-16,944}{2}$

$x_{2} = \frac{1}{-0,118}$