qual e o logaritimo de 2raiz quadrada de 2 de base 2?
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Solução!
![log_{2} 2\sqrt{2}\\\\\\
log_{2} 2\sqrt{2}=x\\\\\\
Lembrando:2 \sqrt{2}=2.2^{ \frac{1}{2} }=2^{ \frac{3}{2} } \\\\\\\
2^{x}=2^{ \frac{3}{2}}\\\\\\
x= \frac{3}{2}\\\\\\\\\\\
\boxed{Resposta: log_{2} 2\sqrt{2}= \frac{3}{2}}](https://tex.z-dn.net/?f=log_%7B2%7D+2%5Csqrt%7B2%7D%5C%5C%5C%5C%5C%5C%0Alog_%7B2%7D+2%5Csqrt%7B2%7D%3Dx%5C%5C%5C%5C%5C%5C+%0ALembrando%3A2+%5Csqrt%7B2%7D%3D2.2%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D%3D2%5E%7B+%5Cfrac%7B3%7D%7B2%7D+%7D+%5C%5C%5C%5C%5C%5C%5C%0A2%5E%7Bx%7D%3D2%5E%7B+%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cfrac%7B3%7D%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A+log_%7B2%7D+2%5Csqrt%7B2%7D%3D+%5Cfrac%7B3%7D%7B2%7D%7D+++ "log_{2} 2\sqrt{2}\\\\\\
log_{2} 2\sqrt{2}=x\\\\\\
Lembrando:2 \sqrt{2}=2.2^{ \frac{1}{2} }=2^{ \frac{3}{2} } \\\\\\\
2^{x}=2^{ \frac{3}{2}}\\\\\\
x= \frac{3}{2}\\\\\\\\\\\
\boxed{Resposta: log_{2} 2\sqrt{2}= \frac{3}{2}}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
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