Question

qual é o limite infinito na 29?

Answer 1

\frac{x+2}{x+3}=\left(x+2\right)\frac{1}{x+3} ok?

\lim _{x\to \:-3+}\left(\left(x+2\right)\frac{1}{x+3}\right)

Aplicando o teorema do limite algebrico:
\left(\lim _{x\to \:-3+}\left(x\right)+2\right)\lim _{x\to \:-3+}\left(\frac{1}{x+3}\right)

\lim _{x\to \:-3+}\left(x\right)=-3

\lim _{x\to \:-3+}\left(\frac{1}{x+3}\right)=\infty 

=(-3+2)∞
= -∞