Question

Qual é o delta de :
x²-x-12=0​

Answer 1

Resposta:

Δ=b²- 4.a.c

$x^{2} -x-12=0$

$a=1\\b=-1\\c=-12$

Δ=b²- 4.a.c

Δ=-1²- 4.1.-12

Δ= $-1^2-4\cdot \:1\cdot \left(-12\right)=47$