Question

qual e o delta de
${x}^{2} - 4x + 4 = 0$

Answer 1

${x}^{2} - 4x + 4 = 0$
a=1
b=-4
c=4

/\= (-4)^2-4×1×4
/\= 16-16
/\=0

$x = \frac{- ( - 4) - + \sqrt{0}}{2} \\ {x}^{1} = \frac{4 + 0}{2} \\ {x}^{1} = 2 \\ \\ {x}^{2} = \frac{4 - 0}{2} \\ {x}^{2} = 2$
Espero ter ajudado