Question

qual é o 8 termo da p.g (_1,4,_16,64,...)?​

Answer 1

Resposta:

$a_n=a_8=?\\ a_1=-1\\ n=8\\ r=q=4\div(-1)=-4\\ \\ Termo~~geral\\ \\ a_n=a_1.q^{n-1}\\ \\ a_8=-1.(-4)^{8-1}\\ \\a_8=-1.(-4)^7\\ \\ a_8=-1.(-16384)\\ \\ a_8=+16384$