Matemática, perguntado por vitorialonghi1263, 6 meses atrás

qual e a soma dos quadrados das raizes da equacao 3x²-2x-5=0​

Soluções para a tarefa

Respondido por JovemLendário
3

\Box \ \ \boxed{\begin{array}{l}\sf  3x^2-2x-5=0\end{array}}\\\\\\\Box \ \ \boxed{\begin{array}{l}\sf a=3 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf b=-2 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf c=-5  \end{array}}\\\\\\

\Box \ \ \boxed{\begin{array}{l}\sf \Delta=b^2-4.a.c \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=(-2)^2-4.3.-5 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=4+60\end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=64 \end{array}} \\\\

\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{-b\pm\sqrt{\Delta}}{2.a}  \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{2\pm8}{2.3}  \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{2\pm8}{6}  \end{array}}\\\\\\\\\Box \ \ \boxed{\begin{array}{l}\sf x'=\frac{2+8}{6}  \end{array}}\boxed{\begin{array}{l}\sf x'=\frac{10}{6}  \end{array}}\\\\

\Box \ \ \boxed{\begin{array}{l}\sf x''=\frac{2-8}{6}  \end{array}}\boxed{\begin{array}{l}\sf x''=\frac{6}{6}  \end{array}}\boxed{\begin{array}{l}\sf x''=1 \end{array}}

Resposta correta;

S=\{1 \ ,\frac{10}{6} \}

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vitorialonghi1263: valeu te amooooh♡
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