Question

qual 'e a solucao para a equacao?
$\sqrt{6 - x} = - x$
​

Answer 1

Resposta:

Explicação passo a passo:

$\sqrt{6-x} =-x\\\\Eleva\:\:ao\:\:quadrado\:\:os\:\:dois\:\:lados\\\\(\sqrt{6-x})^2 =(-x)^2\\\\6-x = x^2\\\\0 = x^2 +x-6\\a=1\\b= 1\\c=-6\\\\\Delta = b^2-4.a.c\\\Delta = 1^2-4*1*(-6)\\\Delta = 1+24=25$

$x'=\frac{-b+\sqrt{\Delta} }{2a} \\\\x'=\frac{-1+\sqrt{25} }{2*1} \\\\x'=\frac{-1+5 }{2} =\frac{4}{2} \\\\x'=2\\\\ou\\\\x''=\frac{-b-\sqrt{\Delta} }{2a} \\\\x''=\frac{-1-\sqrt{25} }{2*1} \\\\x''=\frac{-1-5 }{2} =\frac{-6}{2} \\\\x''=-3$