Question

qual é a resolução desses exercicios?

a resposta da g é -69/16
da h é 5/132

Answer 1

Boa Tarde,
g:
$g= \frac{3}{4}-[(1- \frac{1}{3})^{2}]^{-2} \\\\ g= \frac{3}{4}-[( \frac{1}{1} -\frac{1}{3})^{2}]^{-2} \\\\ g= \frac{3}{4}-[( \frac{2}{3} )^{2}]^{-2} \\\\ g= \frac{3}{4}-[ \frac{4}{9} ]^{-2} \\\\ g= \frac{3}{4}-( \frac{1}{ \frac{16}{81}} ) \\\\ g= \frac{3}{4}- \frac{81}{16} \\\\ g= \frac{12-81}{16} \\\\ g= \frac{-69}{16}$

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h:
$h=( \frac{2}{3} -1)( \frac{-1}{2} ):[( 4-\frac{1}{3} ): \frac{5}{6} ] \\\\ h=( \frac{2}{3} -1)( \frac{-1}{2} ):[( \frac{(4*3)-1}{3} ): \frac{5}{6} ] \\\\ h=( \frac{2}{3} -1)( \frac{-1}{2} ):[ \frac{11}{3} : \frac{5}{6} ] \\\\ h=( \frac{2}{3} -1)( \frac{-1}{2} ):[ \frac{11}{3} * \frac{6}{5} ] \\\\ h=( \frac{2}{3} -1)( \frac{-1}{2} ):[ \frac{22}{5} ] \\\\ h=( \frac{2-(1*3)}{3})( \frac{-1}{2} ):[ \frac{22}{5} ] \\\\ h=( \frac{2-3}{3})( \frac{-1}{2} ):[ \frac{22}{5} ]$
$h=( \frac{-1}{3})( \frac{-1}{2} ):[ \frac{22}{5} ] \\\\ h=( \frac{1}{6} ):[ \frac{22}{5} ] \\\\ h= \frac{1}{6} * \frac{5}{22} \\\\ h= \frac{5}{132}$

Espero Ter Ajudado!!!!! ;-)