qual e a raize de 2x2+7x+3=0
Soluções para a tarefa
Respondido por
7
2x² + 7x + 3 = 0
Δ = 49 - 24
Δ = 25
x = -7 +-√25/4
x = -7 +-5/4
x' = -7+5/4
x' = -2/4
x' = -1/2
x'' = -7-5/4
x'' = -12/4
x'' = -3 S = { -3 , -1/2 } ok
Δ = 49 - 24
Δ = 25
x = -7 +-√25/4
x = -7 +-5/4
x' = -7+5/4
x' = -2/4
x' = -1/2
x'' = -7-5/4
x'' = -12/4
x'' = -3 S = { -3 , -1/2 } ok
Respondido por
3
2x² + 7x + 3 = 0
Δ = b² -4ac
Δ = (7)² -4.(2).(3)
Δ = 49 - 24
Δ = 25
x =
x =
x' = -7 + 5/4
x' = -2/4
x' = -1/2
x" = -7-5/4
x" = -12/4
x" = -3
Δ = b² -4ac
Δ = (7)² -4.(2).(3)
Δ = 49 - 24
Δ = 25
x =
x =
x' = -7 + 5/4
x' = -2/4
x' = -1/2
x" = -7-5/4
x" = -12/4
x" = -3
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