Question

qual  é a  equacoes exponenciais a seguir (3x)x-4=1/27

Answer 1

$(3^x)^{x-4}= \frac{1}{27} \\ \\\not{3}^{x^2-4x}=\not{3}^{-3}\\ \\x^2-4x=-3\\x^2-4x+3=0\\ \\\Delta=(-4)^2-4.1.3\\\Delta=4\\ \\x= \frac{4\pm2}{2} \\ \\x_1=3\\ \\x_2=1$

$\boxed{S=\{3 :1\}}$