Question

Qual é a área do triângulo cujos vértices são A(0,6), B(2,2) e C(5,4) ?

Answer 1

$A_t=|D|*\frac{1}{2}$

$D= \left[\begin{array}{ccc}0&6&1\\2&2&1\\5&4&1\end{array}\right]\\\\\ D=0+30+8-10-12-0\\\\ D=38-22\\\\ \boxed{D=16}$

Portanto, a área do triângulo

$A_t=|D|*\frac{1}{2}\\\\\ A_t=|16|*\frac{1}{2}\\\\ \boxed{A_t=8}$