Question

Qual a soma do quadrado de um numero com o promio numero e 12

Answer 1

Oi

( x² +x)=12
x²+x-12=0
Δ=b²-4.a.c
a=1
b=1
c=-12

Δ=1²-4.1.-12
Δ=1+48
Δ=49

x=$\frac{-b+- \sqrt{delta} }{2.1}$

x=$\frac{-1+- \sqrt{49} }{2}$

x'=$\frac{-1+7}{2}$=$\frac{6}{2}$=$+3$

x"=$\frac{-1-7}{2}$=$\frac{-8}{2}$=-4

S( x'=+3 , x"=-4)

Bons estudos!!