Question

qual a resposta dessa? obrigado

Answer 1

$\frac{2y-2}{5} + \frac{1}{10} - \frac{y.(y+1)}{5} = -\frac{3}{10}$

$\frac{2.(2y-2)}{10} + \frac{1}{10} - \frac{2y.(y+1)}{10} = -\frac{3}{10}$

$2.(2y-2) + 1 - 2y.(y+1) = -3$

$4y-4+1-2 y^{2} -2y+3=0$

$-2 y^{2} +2y=0$

$2 y^{2} -2y=0$

$y^{2} -y=0$

$y.(y-1)=0$

$y=0$
ou
$y-1=0$ ⇒ $y=1$