qual a resolução do log2 base 1/16
Soluções para a tarefa
Respondido por
2
log 1/16= log 1/2*4=log 2*-4= -4 log 2= -4.1=-4
2 2 2 2
2 2 2 2
Respondido por
3
Bom dia Helo!
Solução!
![log2_{ \frac{1}{16}}\\\\
log2_{ \frac{1}{16}}=x\\\\
2^{x}= \frac{1}{16}\\\\\
2^{x}= \frac{1}{2^{4} }\\\\\
2^{x}= 2^{-4} \\\\\
x=-4\\\\\\\\\\\
\boxed{Resposta: log2_{ \frac{1}{16}}~~~x=-4}](https://tex.z-dn.net/?f=log2_%7B+%5Cfrac%7B1%7D%7B16%7D%7D%5C%5C%5C%5C%0Alog2_%7B+%5Cfrac%7B1%7D%7B16%7D%7D%3Dx%5C%5C%5C%5C%0A2%5E%7Bx%7D%3D+%5Cfrac%7B1%7D%7B16%7D%5C%5C%5C%5C%5C%0A2%5E%7Bx%7D%3D+%5Cfrac%7B1%7D%7B2%5E%7B4%7D+%7D%5C%5C%5C%5C%5C%0A2%5E%7Bx%7D%3D+2%5E%7B-4%7D+%5C%5C%5C%5C%5C%0Ax%3D-4%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A++log2_%7B+%5Cfrac%7B1%7D%7B16%7D%7D%7E%7E%7Ex%3D-4%7D%0A++ "log2_{ \frac{1}{16}}\\\\
log2_{ \frac{1}{16}}=x\\\\
2^{x}= \frac{1}{16}\\\\\
2^{x}= \frac{1}{2^{4} }\\\\\
2^{x}= 2^{-4} \\\\\
x=-4\\\\\\\\\\\
\boxed{Resposta: log2_{ \frac{1}{16}}~~~x=-4}")
Bom dia!
Bons estudos!
Solução!
Bom dia!
Bons estudos!
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