Question

Qual a resolução de "x²-6x-1=0"?

Answer 1

$x^2 - 6x - 1 = 0$

Resolvendo por Bháskara.

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1, b=−6, c=−1

Δ=b²−4ac
Δ=(−6)²−4*(1)*(−1)
Δ=36+4
Δ=40

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-6) \pm \sqrt{40}}{2*1} \\ \\ \\ x = \dfrac{6 \pm \sqrt{40}}{2} \\ \\ \\ x = \dfrac{6 \pm 2\sqrt{10}}{2}$

$x' = \dfrac{6 + 2\sqrt{10}}{2} \\ \\ \\ x' = \dfrac{6 + 2\sqrt{10}}{2} \\ \\ \\ x' = {3 + 2\sqrt{10}}$

$x'' = \dfrac{6 - 2\sqrt{10}}{2} \\ \\ \\ x'' = \dfrac{6 - 2\sqrt{10}}{2} \\ \\ \\ x'' = {3 - 2\sqrt{10}}$



S = {${3 + 2\sqrt{10}} \ \ , {3 - 2\sqrt{10}}$}