Question

qual a resoluçao de 25x²-10x-1=0 com bhaskara urgente !!!

Answer 1

$25x^2-10x-1=0\\ \\ \Delta=(-10)^2-4.25.(-1)=100+100=200\\ \\ x=\frac{10 \pm\sqrt{200}}{50}=\frac{10\pm10\sqrt2}{50}=\frac{1\pm\sqrt2}{5}$

Answer 2

$25x^2-10x+1=0$

$\Delta=(-10)^2-4\cdot25\cdot1=100-100=0$

$x=\dfrac{-(-10)\pm\sqrt{0}}{2\cdot25}$

$x'=x"=\dfrac{10}{50}=\dfrac{1}{5}$