Question

Qual a reaposta desse cauculo?

Answer 1

$x^y = 4^1^/^2 = \sqrt{4} = 2$

$y^x = (1/2)^4 = 1/16$

$x^y + y^x = 2* (16/16) + 1/16 \\x^y+ y^x = 31/16$