Question

Qual a razão de cada uma das sequências 1-(1,3,5,7,9...) 2-(-1/2,0,1/2,1,3/2...) 3-(-3,-5,-7,-9,...) 4-(2,4,8,16,32,...) 5-(81,27,9,3,1,1/3...)

Answer 1

1- (1, 3, 5, 7, 9...)    r = 3 - 1 ---- r = 2


2- (-1/2, 0, 1/2, 1, 3/2...)  r = 0 - ( - 1/2) ------ r = 1/2


3-  (-3, -5, -7, -9,...)  ----- r = - 5 - (- 3) ----- r = - 5 + 3 --- r = - 2


4- (2, 4, 8, 16, 32,...)      q = 4/2 ---- q = 2


5- (81, 27, 9, 3, 1, 1/3...) -------- q = 3/9 ----- q = 1/3

Answer 2

$R = a_{n} - a_{(n -1)}$
$Q = \frac{a_{n} }{a_{(n -1)} }$

1)
5 -3
r = 2

2)
0 -(-1/2)
r = 1/2

3)
-5 -(-3)
r = 2

4)
4/2
Q = 2

5)
27/81
3^(3 -4)
Q = 1/3