Question

qual a raiz do polinômio p(x) x2 + 2x - 8 ? (usando a formula de baskara)

Answer 1

x²+2x-8=0

a=1 b=2 c=-8
∆=b²-4.a.c
∆=2²-4.1.(-8)
∆=4+32
∆=36

x=-b±√∆/2.a
x=-2±√36/2.1
x=-2±6/2
x'=-2+6/2=4/2=2
x"=-2-6/2=-8/2=-4

S={(-4,2)}