Question

qual a raiz da equação:
${x}^{2} - 64 + 663 = 0$
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Answer 1

Resposta:

Explicação passo-a-passo:

$x^{2}-64x+663=0\\\\\Delta=(b)^{2}-4(a)(c)=(-64)^{2}-4(1)(663)=4096-(2652)=1444\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-64)-\sqrt{1444}}{2(1)}=\frac{64-38}{2}=\frac{26}{2}=13\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-64)+\sqrt{1444}}{2(1)}=\frac{64+38}{2}=\frac{102}{2}=51$