Question

Qual a primeira determinação positiva de –25/3π rad?

Answer 1

$\mathsf{\dfrac{25\pi}{3}=\dfrac{24\pi}{3}+\dfrac{\pi}{3}}\\\mathsf{8\pi+\dfrac{\pi}{3}=4\times(2\pi)+\dfrac{\pi}{3}}$

$\mathsf{-\dfrac{25\pi}{3}=-4\times(2\pi)-\dfrac{\pi}{3}}$

$\mathsf{2\pi-\dfrac{\pi}{3}=\dfrac{5\pi}{3}}$

$\mathsf{\alpha=\dfrac{5\pi}{3}+2k\pi~k\in\mathbb{Z}}$