Question

Qual a massa de7,8 mols de H3PO4? (H=1g/mol; P=31g/mol e O=16g/mol

Answer 1

Olá!!!

MM(H3PO4) = 3•2+31+4•16 = 98g/mol


1 mol --------- 98g
7.8 mol ----- X

X = 764,4g

ou

m = MM • n

m = 98g/mol • 7.8mol

m = 764,4g