Question

Qual a intensidade do campo elétrico de uma carga elétrica de 12μC, num ambiente em que a constante dielétrica vale k = 9x10^9 Nm²/C², num ponto distante 2 cm dela? (1cm = 1x10-2 m).

Answer 1

$\boxed{F = \frac{KQ^2}{d^2}}\\\\\\\ F = \frac{9.10^9(12.10^-^6)^2}{(2.10^-^2)^2}\\\\\\ F = \frac{9.10^9(144.10^-^1^2)}{4.10^-^4}\\\\\ \boxed{F = 324\ N}$

$\boxed{F = q*E}\\\\\ 324 = 12.10^-^6E\\\\\\ E = \frac{324}{12.10^-^6}\\\\\ \boxed{E = 2,7.10^7\ V}$