Question

Qual a integral x^3√x dx

Answer 1

$\displaystyle \int\,x^3\sqrt{x}\,dx=\int x^3\cdot x^{\frac{1}{2}}\,dx=\int x^{\frac{7}{2}}\,dx=\frac{x^{\frac{9}{2}}}{\frac{9}{2}}+C=\boxed{\frac{2x^{\frac{9}{2}}}{9}+C}$