qual a integral de sqrt(9x/4 + 1 ) ???
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∫√9x/4 +1 dx=∫ 9x+4/4dx=1/2∫√9x+4 dx u=9x +4 du=9dx
1/2.9∫√9x+4 .9dx=1/18∫u*1/2du=1/18(u*3/2)/3/2 +C
=1/27(9x+4)*3/2 +C
1/2.9∫√9x+4 .9dx=1/18∫u*1/2du=1/18(u*3/2)/3/2 +C
=1/27(9x+4)*3/2 +C
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