Question

Qual a fórmula em percentual da molécula C₂₁H₃₀O₂? Dados: C=12, H=1, O=16.​

Answer 1

$\boxed{\begin{array}{l}\sf m=21\cdot12+30\cdot1+2\cdot16\\\sf m=252+30+32=314\\\sf porcentagem~de~C:\\\sf\dfrac{252}{314}\cdot100=80,25\%\\\sf porcentagem~de~H:\\\sf\dfrac{30}{314}\cdot100=9,55\%\\\sf porcentagem~de~O:\\\sf\dfrac{32}{314}\cdot100=10,19\%\\\sf a ~f\acute ormula~percentual~\acute e\\\sf C_{80,25\%}H_{9,55\%}O_{10,19\%}\end{array}}$