Question

Qual a fórmula de Bhaskara X<+6x+9=0

Answer 1

$x ^{2} - 6x + 9 = 0$

$△ = 6 ^{2} - 4ac$

$△ = ( - 6) ^{2} - 4 .1.9 = 36 - 36 = 0$

$x = \frac{ - b - + \sqrt{ △}}{2a}$

$x = \frac{6 - + \sqrt{0} }{2 }$

$= \frac{6}{2} = 3$

$s(3)$