qual a equação biquadrada?
5x⁴-12=0
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5(x²)² - 12 = 0
5y² - 12 = 0
5y² = 12
y² = 12/5
______
y = √12/5
____
y = √4.√3/5
_____
y = + 2√3/5
____
y = - 2√3/5
x² = y
x = √y
******************************************************
_______ __________
___ _____
x = + √2√3/5 e x = - √2 √3/5
***********************************************************
____________
______
x = √- 2√3/5 (não existe para os Reais)
5y² - 12 = 0
5y² = 12
y² = 12/5
______
y = √12/5
____
y = √4.√3/5
_____
y = + 2√3/5
____
y = - 2√3/5
x² = y
x = √y
******************************************************
_______ __________
___ _____
x = + √2√3/5 e x = - √2 √3/5
***********************************************************
____________
______
x = √- 2√3/5 (não existe para os Reais)
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