Question

qual a energia interna de 3 mols de um gas perfeito na temperatura de 27°C? Considere R=8,311/mol k

Answer 1

T = 273 + ºC
T = 273 + 27
T = 300 K

U = 3/2 * n * R * T
U = 3/2 * 3 * 8,311 * 300
U = 11, 21985 KJ