Question

Qual a distância entre os pontos A(-3;11) e B(2;-1)?
A)12
B)13
C)14
D)15
E)16​

Answer 1

Vamos là.

d² = (Ax - Bx)² + (Ay - By)²

d² = (-3 - 2)² + (11 + 1)²

d² = 25 + 144 = 169

d = 13 (B)

Answer 2

$\large\boxed{\begin{array}{l} \sf{d_{AB }=\sqrt{(x_{A} -x_{B})^{2}+(y_{A} -y_{B})^{2}}} \\ \sf{d_{ AB } = \sqrt{( (-3) - 2) {}^{2} + (11 - ( - 1)) {}^{2} } } \\ \sf{d_{AB} = \sqrt{( - 5) {}^{2} + 12 {}^{2} } } \\ \sf{d_{ AB} = \sqrt{25 + 144} } \\ \sf{d_{ AB } = \sqrt{169}} \\ \sf{d_{ AB} = 13}\end{array}}$

$\huge\boxed{ \boxed{ \boxed{ \boxed{ \sf \dagger \blue{ \maltese}~ \red{alternativa~B}}}}}$