Question

qual a derivada de f(x)=tg($\sqrt{x}$)

Answer 1

Resposta:

f(x)= tg(∛5-6x)

df/dx = tg[(5-6x)^1/3]'

df/dx = sec²[(5-6x)^1/3] . [5-6x]^-2/3 . (5 - 6x)'

df/dx = sec²[(5-6x)^1/3] . 1/[3(5-6x)^2/3] . (-6)

df/dx = (-2).sec²[(5 - 6x)^1/3]  /(5-6x)^2/3

Explicação: