Question

quais sao os valores do x do vertice e y do vertice da euqacao y=10x2+20+40?

Answer 1

10x²+20x+40
∆=b²-4ac
∆=(20)²-4(10)*(40)
∆=400-1600
∆=-1200


Xv=-b/2a
Xv=-20/20
Xv=-1

Yv=-∆/4a
Yv=1200/40
Yv=30

Vértice:
(-1,30)