Question

Quais são os maiores valores possíveis para x, y e z de forma que 2x.32.5y.7z seja divisor de 12600.

Answer 1

Resposta:

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\begin{gathered}\sf{5\cdot80=R\$400,00}\\\sf{taxa=\dfrac{400-350}{350}\cdot100=\dfrac{5\diagup\!\!\!0}{35\diagup\!\!\!0}\cdot100=14,28\%}\end{gathered}

5⋅80=R$400,00

taxa=

350

400−350

⋅100=

35╱0

5╱0

⋅100=14,28%

prova real:

\begin{gathered}\sf{100\%+14,28\%=114,28\%=1,1428}\\\sf{350\cdot1,1428=R\$399,98\approx R\$400,00}\end{gathered}

100%+14,28%=114,28%=1,1428

350⋅1,1428=R$399,98≈R$400,00