Question

quais sao as soluçoes da equaçao 2x²-5x+3=0

Answer 1

$\Delta = b^2 - 4ac \\ \Delta = (- 5)^2 - 4 \times 2 \times 3 \\ \Delta 25 - 24 \\ \Delta = 1 \\\\ x = \frac{- b \pm \sqrt{\Delta }}{2a} \Rightarrow x = \frac{- (- 5) \pm 1}{2} \Rightarrow x = \frac{5 \pm 1}{2} \\\\ \begin{cases} x' = \frac{5 + 1}{4} \Rightarrow x' = \frac{6}{4} \Rightarrow \boxed{x' = \frac{3}{2}} \\ x'' = \frac{5 - 1}{4} \Rightarrow x'' = \frac{4}{4} \Rightarrow \boxed{x'' = 1} \end{cases} \\\\ \boxed{\boxed{S = \left \{ 1, \frac{3}{2} \right \}}}$

Answer 2

Olá

 

 2x²-5x+3=0

 

a=2

b=-5

c=3

 

Δ=b²-4*a*c

Δ=(-5)²-4*2*3

Δ=25-24

Δ=1

 

x=-b±√Δ = -(-5)±√1 = 5±1

     2*a             2*2          4

 

x'=5+1 = 3/2

       4

 

x"=5-1 = 1

        4

 

S={3/2,1}