Question

quais sao as raizes reais da equacao x2-x=6?​

Answer 1

² + x - 6 = 0

Δ = b² - 4.a.c

Δ = (1)² - 4.(1).-6)

Δ = 1 + 24

Δ = 25

x = \frac{-b \ ^+_- \ \sqrt{\Delta}}{2.a}2.a−b −+ Δ 

x = \frac{-(1) \ ^+_- \ \sqrt{25}}{2.(1)}2.(1)−(1) −+ 25 

x = \frac{-1 \ ^+_- \ 5}{2}2−1 −+ 5 

x' = \frac{-1 \ + \ 5}{2}2−1 + 5 

x' = \frac{4}{2}24 

x' = 2

x" = \frac{-1 \ - \ 5}{2}2−1 − 5 

x" = \frac{-6}{2}2−6 

x" = -3

Soma das raízes:

x' + x"

2 + (-3)

2 - 3 = -1

Produto entre as raízes:

x' . x"

2 . (-3) = -6

RESPOSTA:

Letra "a" e "b" satisfazem.