Question

Quais são as raizes da equação x2+24-10=0

Answer 1

$\Large\mathsf\displaystyle{} {x}^{2} + 24 - 10 = 0 \\ \Large\mathsf\displaystyle{} {x}^{2} + 14 = 0 \\ \Large\mathsf\displaystyle{} {x}^{2} = - 14 \\\Large\mathsf\displaystyle{}x = \pm \sqrt{ - 14} \\ \\ \Large\mathsf\displaystyle{}x = \pm \sqrt{14\cdot\left( - 1\right)} \\ \\ \Large\mathsf\displaystyle{}x = \pm \sqrt{14} \sqrt{ - 1} \\ \\ \\ \Large\mathsf\displaystyle{}x = \pm \sqrt{14} i \\\\\\ \Large\mathsf\displaystyle{}x = - \sqrt{14} i \\ \\ \Large\mathsf\displaystyle{}x = \sqrt{14} i \\ \\ \LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{ \left(x_{1} = - \sqrt{14}i \right) \\ \left( x_{2} = \sqrt{14}i \right) }}}\end{gathered} }$

$\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{{ \pink{Bons}} \blue{\:Estudos}}}}\end{gathered} }$

Answer 2

Delta = b*2-4•a•c
delta= 24*2-4•2•(-10)
delta= 576-80=496
x=b*2+-raiz de delta
x= 576+-496
x1=576+496=1.072
x2= 576-496=80