Question

Quais são as raízes da equação
x²+10x+16=0?
Me ajudem

Answer 1

x²+10x+16=0

∆ = b² - 4ac
∆ = 10² - 4.1.16
∆ = 100 - 64
∆ = 36

x = - b±√∆ /2a
x = -10±√36 /2.1
x = -10±6 /2

x' = -10 + 6 /2
x' = -4/2
x' = -2

x" = -10 - 6 /2
x" = -16/2
x" = -8

S = {x ∈ R/ x' = -2 ; x" = -8}

Answer 2

$Bhaskara -\ \textgreater \ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
$x^{2} + 10x +16 = 0$

$Delta = (b)^{2} - 4.(a).(c)$
$Delta = (10)^{2} - 4.(1).(16)$
$Delta = 100 - 64$
$Delta = 36$

$x1 = \frac{-(10) + \sqrt{36} }{2} = \frac{-4}{2} = -2$
$x2 = \frac{-(10) - \sqrt{36} }{2} = \frac{-16}{2} = -8$

As raízes são -2 e -8 ✓✓

Espero ter ajudado ^-^