Question

Quais são as raízes da equação x²+10x+16=0​

Answer 1

$a = 1 \\ b = 10 \\ c = 16 \\ \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} \\ x = \frac{ - 10 + - \sqrt{ {10}^{2} - 4 \times 1 \times 16} }{2 \times 1} \\ x = \frac{ - 10 + - \sqrt{100 - 64} }{2 \times 1} \\ x = \frac{ - 10 + - \sqrt{36} }{2} \\ x = \frac{ - 10 + - 6}{2} \\ x = \frac{ - 10 + - 6}{2} \\ x1 = \frac{ - 10 + 6}{2} = \frac{ - 4}{2} = - 2 \\ x2 = \frac{ - 10 - 6}{2} = \frac{ - 16}{2} = - 8$

Answer 2

Resposta: As Raizes sao -2 e -8

Explicação passo-a-passo:x²+10x+16=0

∆= 10²-4.1.16

∆=100-64

∆=36

X¹= -10+√36/2.1=

-10+6/2=

-4/2=

-2

X²= -10-√36/2.1=

-10-6/2

-16/2

-8