Question

quais são as raízes da equação x ao quadrado menos 14x + 48 = 0

Answer 1

$x^2 - 14x + 48$

$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}$


Δ = b²−4ac
Δ = (-14)²−4⋅(1)⋅(48)
Δ = 196−192
Δ = 4


$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\ x = \dfrac{-(-14) \pm \sqrt{4}}{2*1}\\ \\ \\x = \dfrac{14 \pm 2}{2}\\ \\ \\x' = \dfrac{14 + 2}{2}\\ \\ \\x' = \dfrac{16}{2}\\ \\ \\x' = 8\\ \\ \\x'' = \dfrac{14 - 2}{2}\\ \\ \\x'' = \dfrac{12}{2}\\ \\ \\ x'' = 6$

S = {8, 6}