Question

quais sao as raizes da equaçao
$2 { \times }^{2} - 6 \times + 4 = 0$
?​

Answer 1

$a = 2 \ \\ \: \: b = - 6 \\ c =4 \: \\ delta = { - 6}^{2} - 4 \times 2 \times 4 \\ 36 - 32 = 4 \\ \frac{ - ( - 6) + ou - \sqrt{4} }{2 \times 2} \\ \frac{6 + ou - 2}{4} \\ \\ x = \frac{6 + 2}{4} = \frac{8}{4} = 2 \\ \\ x = \frac{6 - 2}{4} = \frac{4}{4} = 1$