Question

quais sao as raizes da equaçao 9(2n-5).(n+2)=0?

Answer 1

9(2n-5)(n+2)=0
9(2n^2 - n - 10) =0
18n^2 - 9n - 90=0 (:9)
2n^2 - n - 10= 0
delta = 81
n'=5/2
n''= -2