Question

Quais são as raízes da equação 6x²-13x+6=0?

Answer 1

Δ = 169 - 144
Δ = 25

x = 13 +-√25/12
x = 13 +-5/12

x' = 13 +5/12
x' = 18/12 = 3/2

x'' = 13 - 5/12
x'' = 8/12 = 2/3     ok

Answer 2

a= 6
b= -13
c= 6

[(-13)^2 -4.6.6]/2.6
169 - 144
delta = 25

[- ( -13) + V25]/ 2.6
13+5/12
18/12 simplifica por 6
3/2

[-(-13) - v25]/2.6
13-5/12
8/12 simplifica por 4
2/3

S= { 2/3, 3/2}