Question

Quais são as raizes da equação 4x^4-37x^2+9=0

Answer 1

x^2=y
4y^2-37y+9=0
Δ=b^2-4ac=(-37)^2-4.4.9=1369-144=1225=35^2
y´=-b+√Δ /2a= -(-37)+35 /8= 72/8= 9
y´´= -b-√Δ /2a= -(-37)-35 /8= 2/8= 1/4

x'^2=y' => x'=√y'= √9 = 3
x''^2=y'' => x''=√y'' = √1/4= 1/2