Question

quais são as raízes da equação 2x²-18x+36=0​

Answer 1

$2x^2-18x+36=0\\\\x_{1,\:2}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\cdot \:2\cdot \:36}}{2\cdot \:2}\\\\x_{1,\:2}=\frac{-\left(-18\right)\pm \:6}{2\cdot \:2}\\\\x_1=\frac{-\left(-18\right)+6}{2\cdot \:2},\:x_2=\frac{-\left(-18\right)-6}{2\cdot \:2}\\\\\\\boxed{x'=6,\:x''=3}$