Question

Quais sao as cordenadas do vértice. Da funcao 2x ao quadrado -4x-6

Answer 1

2x²-4x-6=ax²+bx+c
a=2
b=-4
c=-6
Δ=b²-4*a*c=(-4)²-4*2*(-6)=16+48=64

V=(vx,vy)

vx=-b/2a=4/4=1
vy=-Δ/4a=-64/8=-8  OK

Answer 2

2x² -4x -6=0

Xv= -b/2a
Xv= 4/4
Xv=1

Yv= -D/4a
Yv= -64/8
Yv=-8

S=(1,-8)