Question

Quais os valores de x na equação X^2+ 5x/2 - 3/2=0

Answer 1

$x^2+\frac{5x}{2}-\frac{3}{2}=0\\\\(2)x^2+(2)\frac{5x}{2}-(2)\frac{3}{2}=0\\\\2x^2+5x-3=0$

Calculando Delta :

$\Delta=b^2-4ac=[5]^2 -4[2][-3]=49$

Achando as Raízes :

$x=\frac{-b\pm\sqrt{\Delta}}{2a}=\frac{-5\pm7}{2(2)}=\frac{-5\pm7}{4}\\\\\boxed{x'=\frac{-5+7}{4}=\frac{1}{2}}\\\\\\\boxed{x''=\frac{-5-7}{4}=\frac{-12}{4}=-3}$