Question

quais os quatro primeiros termos da sequencia an= 4n²-2

Answer 1

$\boxed{a_n=4n^2-2}\\ \\ a_1=4*1^2-2=2\\ \\ a_2=4*2^2-2=14\\ \\ a_3=4*3^2-2=34\\ \\ a_4=4*4^2-2=62$