Question

quais as raízes de x² +6x= 2x -3

Answer 1

x²+6x=2x-3 => x²+6x-2x+3=0  => x²+4x+3=0

Δ=b²-4.a.c 
Δ=(4)²-4(1)(3)
Δ=4

raízes:

x=-b+√Δ/2.a
x=-4+√4/2.1
x=-1

ou 

x=-4-√4/2.1
x=-3

Answer 2

$x^{2} +6x=2x-3 \\ x^{2} +6x-2x+3=0 \\ x^{2} +4x+3=0 \\ a=1; b=4; c=3$
$Δ = b^{2} -4ac \\ Δ= 4^{2} -4.1.3 \\ Δ = 4$
Por Bhaskara:
$x= \frac{-4± \sqrt{4} }{2.1} \\ x= \frac{-4±2}{2} \\ x' = \frac{-4+2}{2} =-1 \\ x"= \frac{-4-2}{2} =-3$
raízes: -3 e -1