Question

Quais as raizes da função definida por f(x)=(2x-1) (4x-8)?

Answer 1

Explicação passo-a-passo:

$\sf f(x)=(2x-1)\cdot(4x-8)$

$\sf (2x-1)\cdot(4x-8)=0$

$\sf 2x-1=0~\rightarrow~2x=1~\rightarrow~x'=\dfrac{1}{2}$

$\sf 4x-8=0~\rightarrow~4x=8~\rightarrow~x=\dfrac{8}{2}~\rightarrow~x"=2$

As raízes são $\sf \dfrac{1}{2}~e~2$